A spherical conductor of radius 2 text{ cm} i | vedclass

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(C) The electric field $E$ at a point outside a spherical conductor at a distance $r$ from its center is given by the formula:$E = \frac{1}{4 \pi \var

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$3 	imes 10^{4} 	ext{ Vm}^{-1}$

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(C) The electric field $E$ at a point outside a spherical conductor at a distance $r$ from its center is given by the formula:$E = \frac{1}{4 \pi \varepsilon_{0}} \frac{q}{r^{2}}$Given values:Charge $q = 3 	ext{ nC} = 3 	imes 10^{-9} 	ext{ C}$Distance $r = 3 	ext{ cm} = 3 	imes 10^{-2} 	ext{ m}$Constant $\frac{1}{4 \pi \varepsilon_{0}} = 9 	imes 10^{9} 	ext{ Nm}^{2}	ext{C}^{-2}$Substituting these values into the formula:$E = (9 	imes 10^{9}) 	imes \frac{3 	imes 10^{-9}}{(3 	imes 10^{-2})^{2}}$$E = \frac{9 	imes 10^{9} 	imes 3 	imes 10^{-9}}{9 	imes 10^{-4}}$$E = \frac{27}{9 	imes 10^{-4}} = 3 	imes 10^{4} 	ext{ Vm}^{-1}$Thus,the electric field at a distance of $3 	ext{ cm}$ from the center of the sphere is $3 	imes 10^{4} 	ext{ Vm}^{-1}$.

$A$ spherical conductor of radius $2 \text{ cm}$ is uniformly charged with $3 \text{ nC}$. What is the electric field at a distance of $3 \text{ cm}$ from the center of the sphere?

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