A student has to answer 10 questions,choosing | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given,total questions in part $A = 6$ and total questions in part $B = 7$. To choose $10$ questions with at least $4$ from each part,the possible

Vedclass · Accepted Answer

$266$

Vedclass · Answer

(C) Given,total questions in part $A = 6$ and total questions in part $B = 7$. To choose $10$ questions with at least $4$ from each part,the possible combinations are: $1$. $4$ from part $A$ and $6$ from part $B$ $2$. $5$ from part $A$ and $5$ from part $B$ $3$. $6$ from part $A$ and $4$ from part $B$ Total ways = $({ }^{6}C_{4} 	imes { }^{7}C_{6}) + ({ }^{6}C_{5} 	imes { }^{7}C_{5}) + ({ }^{6}C_{6} 	imes { }^{7}C_{4})$ $= (15 	imes 7) + (6 	imes 21) + (1 	imes 35)$ $= 105 + 126 + 35 = 266$

$A$ student has to answer $10$ questions,choosing at least $4$ from each of the parts $A$ and $B$. If there are $6$ questions in part $A$ and $7$ in part $B$,then the number of ways the student can choose $10$ questions is:

Similar Questions

$A$ committee of $7$ members is to be formed from $9$ boys and $4$ girls. In how many ways can this be done if the committee must consist of at least $3$ girls?

There are $7$ identical white balls and $3$ identical black balls. The number of distinguishable arrangements in a row of all the balls,so that no two black balls are adjacent is

If $^nC_4, ^nC_5,$ and $^nC_6$ are in $A.P.,$ then $n$ can be

In how many ways can a team of $3$ boys and $3$ girls be selected from $5$ boys and $4$ girls?

The least value of a natural number $n$ such that $\binom{n-1}{5} + \binom{n-1}{6} < \binom{n}{7}$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module