(B) Given: Length of the rod $l = 2 \, m$, speed $v = 5 \, ms^{-1}$, magnetic field $B = 0.04 \, T$, and resistance $R = 3 \, \Omega$.The motional ele

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(B) Given: Length of the rod $l = 2 \, m$, speed $v = 5 \, ms^{-1}$, magnetic field $B = 0.04 \, T$, and resistance $R = 3 \, \Omega$.The motional electromotive force $(EMF)$ induced in the rod is given by:$\varepsilon = B l v$$\varepsilon = 0.04 \, T \times 2 \, m \times 5 \, ms^{-1} = 0.4 \, V$The current $I$ induced in the rod is given by Ohm's law:$I = \frac{\varepsilon}{R}$$I = \frac{0.4 \, V}{3 \, \Omega} = 0.1333... \, A$$I \approx 0.133 \, A = 133 \, mA$.

Class 12 Physics Electromagnetic Induction Motional EMI (Induced Parameter)

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$A$ rod of length $2 \, m$ slides with a speed of $5 \, ms^{-1}$ on a rectangular conducting frame as shown in the figure. There exists a uniform magnetic field of $0.04 \, T$ perpendicular to the plane of the figure. If the resistance of the rod is $3 \, \Omega$, the current through the rod is

KCET 2020 All KCET

A
$75 \, mA$
B
$133 \, mA$
C
$0.75 \, A$
D
$1.33 \, A$

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Class 12

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Electromagnetic Induction

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Motional EMI (Induced Parameter)

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EasyIIT 1998

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$A$ rectangular loop $PQRS$ is being pulled with a constant speed into a uniform transverse magnetic field by a force $F$ (as shown). The $e.m.f.$ induced in side $PS$ and the potential difference between points $P$ and $S$ respectively are (Resistance of the loop $= r$)

Medium

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$A$ thin semicircular conducting ring of radius $R$ is falling with its plane vertical in a horizontal magnetic induction $B$. At the position $MNQ$,the speed of the ring is $V$ and the potential difference developed across the ring is

MediumIIT 1996

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$A$ rod of length $2 \, m$ slides with a speed of $5 \, ms^{-1}$ on a rectangular conducting frame as shown in the figure. There exists a uniform magnetic field of $0.04 \, T$ perpendicular to the plane of the figure. If the resistance of the rod is $3 \, \Omega$, the current through the rod is

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The loop shown moves with a constant velocity $V$ in a uniform magnetic field of magnetic induction $B$ directed into the paper. The potential difference between $P$ and $Q$ is:

$A$ metal rod moves at a constant velocity in a direction perpendicular to its length. $A$ constant uniform magnetic field exists in space in a direction perpendicular to the rod as well as its velocity. Select the correct statement$(s)$ from the following.

$A$ rectangular loop $PQRS$ is being pulled with a constant speed into a uniform transverse magnetic field by a force $F$ (as shown). The $e.m.f.$ induced in side $PS$ and the potential difference between points $P$ and $S$ respectively are (Resistance of the loop $= r$)

$A$ thin semicircular conducting ring of radius $R$ is falling with its plane vertical in a horizontal magnetic induction $B$. At the position $MNQ$,the speed of the ring is $V$ and the potential difference developed across the ring is

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