$A$ planet moving around the Sun sweeps out an area $A_{1}$ in $2$ days,$A_{2}$ in $3$ days,and $A_{3}$ in $6$ days. Then,the relation between $A_{1}, A_{2}$,and $A_{3}$ is

  • A
    $6 A_{1} = 3 A_{2} = 2 A_{3}$
  • B
    $3 A_{1} = 2 A_{2} = A_{3}$
  • C
    $2 A_{1} = 3 A_{2} = 6 A_{3}$
  • D
    $3 A_{1} = 2 A_{2} = 6 A_{3}$

Explore More

Similar Questions

$A$ planet has an orbital radius twice that of the Earth's orbital radius. The time period of the planet is .......... $years$.

The motion of planets in the solar system is an example of the conservation of:

Out of aphelion and perihelion,where is the speed of the earth more and why?

Difficult
View Solution

The distance of a planet from the sun is $5$ times the distance between the earth and the sun. The time period of the planet is

The figure shows the elliptical path $abcd$ of a planet around the sun $S$ such that the area of triangle $csa$ is $\frac{1}{4}$ of the area of the ellipse. With $db$ as the major axis and $ca$ as a chord perpendicular to the major axis,if $t_1$ is the time taken for the planet to travel along the path $abc$ and $t_2$ is the time taken for the path $cda$,then:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo