A moving coil galvanometer is converted into | vedclass

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(D) Given: Shunt resistance $S = 10 \, \Omega$, Galvanometer resistance $G = 90 \, \Omega$, Total range $i = 5 \, mA = 5 	imes 10^{-3} \, A$.The numb

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$1 	imes 10^5 \, div/A$

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(D) Given: Shunt resistance $S = 10 \, \Omega$, Galvanometer resistance $G = 90 \, \Omega$, Total range $i = 5 \, mA = 5 	imes 10^{-3} \, A$.The number of divisions on one side of zero is $50$.The current $i_g$ flowing through the galvanometer at full-scale deflection is given by the shunt formula: $i_g = \frac{S}{S+G} 	imes i$.$i_g = \left( \frac{10}{10+90} ight) 	imes (5 	imes 10^{-3} \, A) = \left( \frac{10}{100} ight) 	imes 5 	imes 10^{-3} \, A = 0.1 	imes 5 	imes 10^{-3} \, A = 5 	imes 10^{-4} \, A$.Current sensitivity is defined as the number of divisions per unit current: $	ext{Sensitivity} = \frac{	ext{Number of divisions}}{i_g}$.$	ext{Sensitivity} = \frac{50}{5 	imes 10^{-4} \, A} = 10 	imes 10^4 \, div/A = 1 	imes 10^5 \, div/A$.

$A$ moving coil galvanometer is converted into an ammeter of range $0$ to $5 \, mA$. The galvanometer resistance is $90 \, \Omega$ and the shunt resistance has a value of $10 \, \Omega$. If there are $50$ divisions in the galvanometer-turned-ammeter on either side of zero, its current sensitivity is

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