$ \chi_{1} $ and $ \chi_{2} $ are the magnetic susceptibilities of a paramagnetic material at temperatures $ T_{1} \ K $ and $ T_{2} \ K $ respectively. Then:

$A$ magnetic intensity of $500 \,A/m$ produces a magnetic flux of $2.4 \times 10^{-5} \,Wb$ in an iron bar of cross-sectional area $0.4 \,cm^2$. The magnetic permeability of the iron bar is

$A$ rod of ferromagnetic material with dimensions $10 \, cm \times 0.5 \, cm \times 0.2 \, cm$ is placed in a magnetic field of strength $0.5 \times 10^4 \, Am^{-1}$. As a result,a magnetic moment of $5 \, Am^2$ is produced in the rod. The value of magnetic induction will be.... $T$

An iron bar having a cross-sectional area of $2 \times 10^{-5} \ m^2$ and a magnetising field of $2400 \ A/m$ produces a magnetic flux of $2.4 \pi \times 10^{-5} \ Wb$. What will be the value of permeability $(\mu)$ and susceptibility $(\chi)$ of the bar? (Given $\mu_0 = 4 \pi \times 10^{-7} \ T \cdot m/A$)

By putting a magnetic substance of volume $30\, cm^3$ in a magnetising field of strength $\frac{1250}{\pi} \, A/m$,the value of the produced magnetic moment is $6\, A\cdot m^2$. Calculate the value of magnetic induction produced in the substance in $T$.

The magnetic susceptibility of a paramagnetic material is $99$. The permeability of the material in $Wb / A-m$ is: [Permeability of free space $\mu_{0} = 4 \pi \times 10^{-7} \ Wb / A-m$]