A fish in water (refractive index n) looks at | vedclass

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(B) When an observer is in a denser medium (water,refractive index $n$) and the object (bird) is in a rarer medium (air,refractive index $1$),the appa

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$x+ny$

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(B) When an observer is in a denser medium (water,refractive index $n$) and the object (bird) is in a rarer medium (air,refractive index $1$),the apparent height of the object is increased.For an observer in a medium of refractive index $n$,the apparent height $h'$ of an object at a real height $h$ is given by $h' = n 	imes h$.Here,the bird is at a height $y$ above the water surface.Therefore,the apparent height of the bird as seen by the fish from the water surface is $h' = n 	imes y$.The fish is at a depth $x$ below the water surface.Thus,the total distance of the bird as estimated by the fish is the sum of the depth of the fish and the apparent height of the bird: $D = x + ny$.

$A$ fish in water (refractive index $n$) looks at a bird vertically above in the air. If $y$ is the height of the bird and $x$ is the depth of the fish from the surface,then the distance of the bird as estimated by the fish is

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