A car moves from A to B with a speed of 30 k | vedclass

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(B) Let the distance between $A$ and $B$ be $d$.Time taken to travel from $A$ to $B$ is $t_{1} = \frac{d}{v_{1}} = \frac{d}{30}$.Time taken to travel

Vedclass · Accepted Answer

$24$

Vedclass · Answer

(B) Let the distance between $A$ and $B$ be $d$.Time taken to travel from $A$ to $B$ is $t_{1} = \frac{d}{v_{1}} = \frac{d}{30}$.Time taken to travel from $B$ to $A$ is $t_{2} = \frac{d}{v_{2}} = \frac{d}{20}$.Average speed is defined as the total distance divided by the total time.Average speed $= \frac{	ext{Total distance}}{	ext{Total time}} = \frac{d + d}{t_{1} + t_{2}} = \frac{2d}{\frac{d}{30} + \frac{d}{20}}$.Average speed $= \frac{2d}{d(\frac{20 + 30}{600})} = \frac{2 	imes 600}{50} = \frac{1200}{50} = 24 \ km/h$.

$A$ car moves from $A$ to $B$ with a speed of $30 \ km/h$ and from $B$ to $A$ with a speed of $20 \ km/h$. What is the average speed of the car (in $km/h$)?

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