$1 \ \text{mole}$ of $NaCl$ is doped with $10^{-5} \ \text{mole}$ of $SrCl_{2}$. The number of cationic vacancies in the crystal lattice will be:

  • A
    $6.022 \times 10^{23}$
  • B
    $12.044 \times 10^{20}$
  • C
    $6.022 \times 10^{18}$
  • D
    $6.022 \times 10^{15}$

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