80 g of oxygen contains as many atoms as in | vedclass

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Question

(D) The molar mass of oxygen atoms $(O)$ is $16 \ g/mol$. However,oxygen gas exists as $O_2$. Number of moles of $O_2 = \frac{80 \ g}{32 \ g/mol} = 2.

Vedclass · Accepted Answer

$5 \ g$ of hydrogen

Vedclass · Answer

(D) The molar mass of oxygen atoms $(O)$ is $16 \ g/mol$. However,oxygen gas exists as $O_2$. Number of moles of $O_2 = \frac{80 \ g}{32 \ g/mol} = 2.5 \ mol$. Number of oxygen atoms $= 2.5 \ mol 	imes 2 	imes N_A = 5 	imes N_A$. For hydrogen gas $(H_2)$,the molar mass is $2 \ g/mol$. Number of atoms in $5 \ g$ of $H_2$: Moles of $H_2 = \frac{5 \ g}{2 \ g/mol} = 2.5 \ mol$. Number of hydrogen atoms $= 2.5 \ mol 	imes 2 	imes N_A = 5 	imes N_A$. Thus,$80 \ g$ of oxygen contains the same number of atoms as $5 \ g$ of hydrogen.

$80 \ g$ of oxygen contains as many atoms as in

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