$A$ $6 \%$ solution of urea is isotonic with

  • A
    $1 \ M$ solution of glucose
  • B
    $0.05 \ M$ solution of glucose
  • C
    $6 \%$ solution of glucose
  • D
    $25 \%$ solution of glucose

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Similar Questions

Define $Hypertonic$ solution and $Hypotonic$ solution.

$A$ solution containing $10 \ g$ of urea (molar mass $= 60 \ g \ mol^{-1}$) per liter is isotonic with a $5 \% \ w/v$ solution of a non-volatile solute. The molar mass of the non-volatile solute is ......... $g \ mol^{-1}$.

Solution $A$ is prepared by dissolving $1 \text{ g}$ of a protein (molar mass = $50000 \text{ g mol}^{-1}$) in $0.5 \text{ L}$ of water at $300 \text{ K}$. Its osmotic pressure is $x \text{ bar}$. Solution $B$ is made by dissolving $2 \text{ g}$ of the same protein in $1 \text{ L}$ of water at $300 \text{ K}$. The osmotic pressure of solution $B$ is $y \text{ bar}$. The entire solution of $A$ is mixed with the entire solution of $B$ at the same temperature. The osmotic pressure of the resultant solution is $z \text{ bar}$. $x, y$ and $z$ respectively are: $(R = 0.083 \text{ L bar mol}^{-1} \text{ K}^{-1})$

An artificial cell is made by encapsulating $0.2 \ M$ glucose solution within a semipermeable membrane. The osmotic pressure developed when the artificial cell is placed within a $0.05 \ M$ solution of $NaCl$ at $300 \ K$ is . . . . . . . . . .$\times 10^{-1} \ bar$. (Nearest Integer)
[Given : $R=0.083 \ L \ bar \ mol^{-1} \ K^{-1}$ ]
Assume complete dissociation of $NaCl$.

$A$ solution containing $10 \ g$ per $dm^3$ of urea (molecular mass $= 60 \ g \ mol^{-1}$) is isotonic with a $5 \%$ solution of a non-volatile solute. The molecular mass of this non-volatile solute is ........ $g \ mol^{-1}$.

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