(A) In step-$1$,$CH_3 CH_2 OH$ is converted to $CH_3 CHO$ by $Cl_2$. This is an oxidation reaction where the primary alcohol group $(-CH_2 OH)$ is oxi

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(A) In step-$1$,$CH_3 CH_2 OH$ is converted to $CH_3 CHO$ by $Cl_2$. This is an oxidation reaction where the primary alcohol group $(-CH_2 OH)$ is oxidized to an aldehyde group $(-CHO)$.In step-$2$,$CH_3 CHO$ reacts with $3 Cl_2$ to form $Cl_3 C CHO$. This is a chlorination reaction where the hydrogen atoms of the methyl group are substituted by chlorine atoms.

Class 12 Chemistry Alcohols, Phenols and Ethers Properties of alcohol

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$CH_3 CH_2 OH \underset{\text{step-}1}{\stackrel{Cl_2}{\longrightarrow}} CH_3 CHO$ $\underset{\text{step-}2}{\stackrel{3 Cl_2}{\longrightarrow}} Cl_3 CCHO$
In the above reactions,the role of $Cl_2$ in step-$1$ and step-$2$ respectively is:

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A
oxidation,chlorination
B
reduction,chlorination
C
oxidation,addition
D
reduction,substitution

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Alcohols, Phenols and Ethers

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Properties of alcohol

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$CH_3 CH_2 OH \underset{\text{step-}1}{\stackrel{Cl_2}{\longrightarrow}} CH_3 CHO$ $\underset{\text{step-}2}{\stackrel{3 Cl_2}{\longrightarrow}} Cl_3 CCHO$In the above reactions,the role of $Cl_2$ in step-$1$ and step-$2$ respectively is:

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Which alcohol gives instant turbidity with Lucas reagent?

Ethanol,when reacted with $PCl_5$,gives $A$,$POCl_3$,and $HCl$. $A$ reacts with silver nitrite $(AgNO_2)$ to form $B$ (major product) and $AgCl$. $A$ and $B$ are respectively:

In the following reaction sequence,$X$ and $Y$,respectively,are:$CH_2=C(CH_3)_2$ $\xrightarrow{X} \text{Epoxide}$ $\xrightarrow{Y} (CH_3)_3C-OH$

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$CH_3 CH_2 OH \underset{\text{step-}1}{\stackrel{Cl_2}{\longrightarrow}} CH_3 CHO$ $\underset{\text{step-}2}{\stackrel{3 Cl_2}{\longrightarrow}} Cl_3 CCHO$
In the above reactions,the role of $Cl_2$ in step-$1$ and step-$2$ respectively is:

In the following reaction sequence,$X$ and $Y$,respectively,are:
$CH_2=C(CH_3)_2$ $\xrightarrow{X} \text{Epoxide}$ $\xrightarrow{Y} (CH_3)_3C-OH$