A carbonyl compound X (C_3H_6O) on oxidation | vedclass

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Question

(C) The carbonyl compound $X$ has the molecular formula $C_3H_6O$. On oxidation,it gives a carboxylic acid $Y$ with the formula $C_3H_6O_2$. Since the

Vedclass · Accepted Answer

$CH_3-CH_2-CH=NOH$

Vedclass · Answer

(C) The carbonyl compound $X$ has the molecular formula $C_3H_6O$. On oxidation,it gives a carboxylic acid $Y$ with the formula $C_3H_6O_2$. Since the number of carbon atoms remains the same ($3$ carbons) during oxidation,$X$ must be an aldehyde (propanal,$CH_3-CH_2-CHO$). Ketones with $3$ carbons would undergo cleavage and produce acids with fewer carbon atoms. Therefore,$X$ is propanal $(CH_3-CH_2-CHO)$. The reaction of an aldehyde with hydroxylamine $(NH_2OH)$ forms an oxime: $CH_3-CH_2-CHO + NH_2OH \rightarrow CH_3-CH_2-CH=NOH + H_2O$. Thus,the oxime of $X$ is $CH_3-CH_2-CH=NOH$.

$A$ carbonyl compound $X$ $(C_3H_6O)$ on oxidation gives a carboxylic acid $Y$ $(C_3H_6O_2)$. The oxime of $X$ is:

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