A coil of inductive reactance frac{1}{sqrt{3} | vedclass

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(B) Given: Inductive reactance $X_L = \frac{1}{\sqrt{3}} \ \Omega$,Resistance $R = 1 \ \Omega$,Frequency $f = 50 \ Hz$.In an $LR$ series circuit,the p

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$\frac{1}{600} \ s$

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(B) Given: Inductive reactance $X_L = \frac{1}{\sqrt{3}} \ \Omega$,Resistance $R = 1 \ \Omega$,Frequency $f = 50 \ Hz$.In an $LR$ series circuit,the phase angle $\phi$ is given by $	an \phi = \frac{X_L}{R}$.$	an \phi = \frac{1/\sqrt{3}}{1} = \frac{1}{\sqrt{3}}$.Therefore,$\phi = 30^{\circ} = \frac{\pi}{6} \ 	ext{radians}$.The phase difference $\phi$ is related to the time lag $\Delta t$ by the formula $\phi = \omega \Delta t$,where $\omega = 2\pi f$.$\omega = 2 	imes \pi 	imes 50 = 100\pi \ 	ext{rad/s}$.Substituting the values: $\frac{\pi}{6} = 100\pi 	imes \Delta t$.$\Delta t = \frac{\pi}{6 	imes 100\pi} = \frac{1}{600} \ s$.Thus,the time lag is $\frac{1}{600} \ s$.

$A$ coil of inductive reactance $\frac{1}{\sqrt{3}} \Omega$ and a resistance $1 \Omega$ are connected in series to a $200 \ V, 50 \ Hz$ ac source. The time lag between voltage and current is

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