A frac{50}{pi} mu F capacitor is connected to | vedclass

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(A) Given: Capacitance $C = \frac{50}{\pi} \mu F = \frac{50}{\pi} 	imes 10^{-6} \, F$. Source voltage $V_{rms} = 250 \, V$ and frequency $f = 50 \, H

Vedclass · Accepted Answer

$1.25$

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(A) Given: Capacitance $C = \frac{50}{\pi} \mu F = \frac{50}{\pi} 	imes 10^{-6} \, F$. Source voltage $V_{rms} = 250 \, V$ and frequency $f = 50 \, Hz$. The capacitive reactance $X_C$ is given by the formula $X_C = \frac{1}{2 \pi f C}$. Substituting the values: $X_C = \frac{1}{2 \pi 	imes 50 	imes (\frac{50}{\pi} 	imes 10^{-6})} = \frac{1}{100 	imes 50 	imes 10^{-6}} = \frac{1}{5000 	imes 10^{-6}} = \frac{1}{0.005} = 200 \, \Omega$. The rms current $I_{rms}$ is given by $I_{rms} = \frac{V_{rms}}{X_C}$. $I_{rms} = \frac{250}{200} = 1.25 \, A$.

$A$ $\frac{50}{\pi} \mu F$ capacitor is connected to a $250 \, V, 50 \, Hz$ $AC$ supply. Then the rms current of the circuit is (in $ \, A$)

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