$A$ bulb of resistance $280 \Omega$ is supplied with a $200 V$ $AC$ supply. What is the peak current?

An alternating current is given by $i = i_1 \sin \omega t + i_2 \cos \omega t$. The rms current is given by

An alternating current is represented by the equation,$i = 100 \sqrt{2} \sin(100 \pi t) \ A$. The $\text{RMS}$ value of current and the frequency of the given alternating current are:

$A$ resistance of $40 \,\Omega$ is connected to a source of alternating current rated $220 \,V, 50 \,Hz$. Find the time taken by the current to change from its maximum value to its $rms$ value.

The average value of alternating current $I = I_0 \sin \omega t$ in the time interval $[0, \frac{\pi}{\omega}]$ is:

The output of a step-down transformer is measured to be $24 \ V$,when connected to a $12 \ W$ light bulb. The value of peak current is $...... \ A$. (in $A$)