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(A) The current $I$ in a conductor is given by $I = nAev_d$,where $n$ is the number density of electrons,$A$ is the cross-sectional area,$e$ is the ch

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$I/s$

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(A) The current $I$ in a conductor is given by $I = nAev_d$,where $n$ is the number density of electrons,$A$ is the cross-sectional area,$e$ is the charge of an electron,and $v_d$ is the drift velocity.The total number of electrons in a length $l$ of the conductor is $N = nAl$.The total momentum $P$ of these electrons is $P = Nmv_d = (nAl)mv_d$,where $m$ is the mass of an electron.We can rewrite the expression for current as $v_d = I / (nAe)$.Substituting $v_d$ into the momentum equation: $P = nAlm 	imes (I / (nAe)) = (lmI) / e$.The specific charge $s$ is defined as $s = e/m$,which implies $m/e = 1/s$.Therefore,the momentum per unit length is $P/l = (mI) / e = I / s$.

$A$ straight conductor of uniform area of cross-section carries a current $I$. If $s$ is the specific charge (charge-to-mass ratio) of the electron,what is the total momentum of all the electrons per unit length of the conductor due to their drift velocity?

Similar Questions

$A$ conductor wire having $10^{29}$ free electrons $/ m^{3}$ carries a current of $20 \,A$. If the cross-section of the wire is $1 \,mm^{2}$, then the drift velocity of electrons will be. $\left(e=1.6 \times 10^{-19} \,C\right)$

Explain the mobility of a charge carrier in a conductor and derive its equation.

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Drift speed $(v_d)$ varies with the intensity of the electric field $(E)$ as per the relation:

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