$A$ constant potential difference is applied between the ends of a wire. If the length of the wire is elongated to $4$ times its original length,then the drift velocity of electrons will be:

In the presence of an electric field,is the path of a free electron between two successive collisions a straight line?

The number density of free electrons in a copper conductor is estimated to be $8.5 \times 10^{28} \ m^{-3}$. How long does an electron take to drift from one end of a wire $6 \ m$ long to its other end? The area of cross-section of the wire is $1.0 \times 10^{-6} \ m^2$ and it is carrying a current of $1.5 \ A$.

An electron takes $40 \times 10^3 \ s$ to drift from one end of a metal wire of length $2 \ m$ to its other end. The area of cross-section of the wire is $4 \ mm^2$ and it is carrying a current of $1.6 \ A$. The number density of free electrons in the metal wire is

When a potential difference is applied across a linear metallic conductor,then:

The drift velocity of an electron is $v_d$ in a conductor of area of cross-section $A$ and carries a current $I$. Now, the area of cross-section and current flowing through the conductor are doubled, then the new drift velocity of the electron is . . . . . . .