A galvanometer,having a resistance of 50 Omeg | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Resistance of galvanometer,$G = 50 \Omega$.Full-scale current,$i_g = 0.05 	ext{ A}$.Area of cross-section,$A = 2.97 	imes 10^{-2} 	ext{ cm}^2 =

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) Resistance of galvanometer,$G = 50 \Omega$.Full-scale current,$i_g = 0.05 	ext{ A}$.Area of cross-section,$A = 2.97 	imes 10^{-2} 	ext{ cm}^2 = 2.97 	imes 10^{-6} 	ext{ m}^2$.Maximum current to be measured,$i = 5 	ext{ A}$.Specific resistance,$ho = 5 	imes 10^{-7} \Omega	ext{-m}$.The shunt resistance $S$ required to convert the galvanometer into an ammeter is given by $S = \frac{i_g G}{i - i_g}$.$S = \frac{0.05 	imes 50}{5 - 0.05} = \frac{2.5}{4.95} = \frac{250}{495} = \frac{50}{99} \Omega$.Since $S = ho \frac{l}{A}$,we have $l = \frac{S \cdot A}{ho}$.$l = \frac{50}{99} 	imes \frac{2.97 	imes 10^{-6}}{5 	imes 10^{-7}} = \frac{50}{99} 	imes \frac{29.7}{5} = 10 	imes 0.3 = 3 	ext{ m}$.

Similar Questions

The equation of the bisectors of the angle between the lines represented by $3 x^2-5 x y+4 y^2=0$ is

$A$ metal rod of length $2 \text{ m}$ has cross-sectional areas $2A$ and $A$ as shown in the figure. The ends are maintained at temperatures $100^{\circ}\text{C}$ and $70^{\circ}\text{C}$. The temperature at the middle point $C$ is...... $^{\circ}\text{C}$

Which of the following compounds contains an $S - S$ bond?

For the given logic gate circuit, which of the following is the correct truth table?

Observe the following statements regarding the purification of bauxite:
$I$. During Hall's process,silica is removed as $Si$ (vapour).
$II$. Bauxite ore contaminated with $Fe_2O_3$ is purified in Baeyer's process.
$III$. During Serpeck's process,$AlN$ is formed.
The correct answer is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module