$A$ point charge '$q$' coulomb is placed at the centre of a cube of side length '$L$'. Then the electric flux linked with each face of the cube is

$A$ hollow cylinder has a charge $q$ at its center. If $\phi$ is the electric flux associated with the curved surface $B,$ the flux linked with the plane surface $A$ will be $:-$

$A$ point charge causes an electric flux of $-1.0 \times 10^{3} \; N \cdot m^{2} / C$ to pass through a spherical Gaussian surface of $10.0 \; cm$ radius centered on the charge.
$(a)$ If the radius of the Gaussian surface were doubled,how much flux would pass through the surface?
$(b)$ What is the value of the point charge?

$A$ charge $q$ is placed at the center of the circular base of an inverted cone of height $h$ and base radius $R$. The cone is capped by a hemisphere of radius $R$ as shown in the figure. The electric flux through the conical surface is $\frac{n q}{6 \epsilon_0}$ (in $SI$ units). The value of $n$ is. . . .

$A$ cubical region of side $a$ has its centre at the origin. It encloses three fixed point charges,$-q$ at $(0, -a/4, 0)$,$+3q$ at $(0, 0, 0)$,and $-q$ at $(0, +a/4, 0)$. Choose the correct option$(s)$.
$(A)$ The net electric flux crossing the plane $x = +a/2$ is equal to the net electric flux crossing the plane $x = -a/2$.
$(B)$ The net electric flux crossing the plane $y = +a/2$ is more than the net electric flux crossing the plane $y = -a/2$.
$(C)$ The net electric flux crossing the entire region is $\frac{q}{\varepsilon_0}$.
$(D)$ The net electric flux crossing the plane $z = +a/2$ is equal to the net electric flux crossing the plane $x = +a/2$.

$A$ linear charge having linear charge density $\lambda$ penetrates a cube of side length $a$ diagonally and then it penetrates a sphere of radius $a$ diametrically as shown. What will be the ratio of the electric flux coming out of the cube to that of the sphere?