2-methyl-2-butene on hydration gives an alcoh | vedclass

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(B) The hydration of $2-$methyl$-2-$butene $(CH_3-C(CH_3)=CH-CH_3)$ follows Markovnikov's rule to form $2-$methyl$-2-$butanol $(X)$,which is a tertiar

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Acetaldehyde + Isopropylmagnesium bromide followed by hydrolysis

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(B) The hydration of $2-$methyl$-2-$butene $(CH_3-C(CH_3)=CH-CH_3)$ follows Markovnikov's rule to form $2-$methyl$-2-$butanol $(X)$,which is a tertiary alcohol $(CH_3-C(OH)(CH_3)-CH_2-CH_3)$.An isomer of $X$ is $3-$methyl$-2-$butanol $(CH_3-CH(OH)-CH(CH_3)_2)$,which is a secondary alcohol.This isomer can be prepared by the reaction of acetaldehyde $(CH_3CHO)$ with isopropylmagnesium bromide $((CH_3)_2CHMgBr)$ followed by hydrolysis,as this is a Grignard reaction forming a secondary alcohol.Thus,option $(B)$ is correct.

$2-$methyl$-2-$butene on hydration gives an alcohol $X$. An isomer of $X$ could be prepared from which of the following?

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