$A$ polyatomic gas with $n$ degrees of freedom has a mean kinetic energy per molecule given by (if $K$ is Boltzmann's constant):

How many degrees of freedom does a diatomic gas have due to its translational motion?

For a gas, $\frac{R}{C_v} = 0.4$, where $R$ is the universal gas constant and $C_v$ is the molar specific heat at constant volume. The gas is made up of molecules which are

Energy of $10$ non-rigid diatomic molecules at temperature $T$ is:

$A$ diatomic gas consisting of rigid molecules is at a temperature of $87^{\circ} C$. If the moment of inertia of the rotating diatomic rigid molecule is $2.76 \times 10^{-46} kg \cdot m^2$,then the rms angular speed of the molecule is (Boltzmann constant $= 1.38 \times 10^{-23} J \cdot K^{-1}$)

If one mole of a polyatomic gas has two vibrational modes and $\beta$ is the ratio of molar specific heats for the polyatomic gas $\left(\beta=\frac{C_{P}}{C_{V}}\right)$,then the value of $\beta$ is: