$A$ block of mass $8 \ kg$ is suspended by a rope of length $3 \ m$ from the ceiling. $A$ force of $40 \ N$ is applied horizontally to the block. Then the angle that the rope makes with the vertical in equilibrium is (acceleration due to gravity $= 10 \ m \ s^{-2}$,neglect the mass of the rope).
- A$\sin ^{-1}\left(\frac{1}{2}\right)$
- B$\tan ^{-1}\left(\frac{1}{2}\right)$
- C$\sin ^{-1}\left(\frac{1}{3}\right)$
- D$\tan ^{-1}\left(\frac{1}{3}\right)$
Explore More
Similar Questions
$A$ body of mass $m$ is suspended by two strings making angles $\theta_1$ and $\theta_2$ with the horizontal ceiling with tensions $T_1$ and $T_2$ respectively. If $T_1 = \sqrt{3} T_2$,then the angles $\theta_1$ and $\theta_2$ are:
DifficultJEE MAIN 2025
View SolutionTwo like parallel forces $20 \,N$ and $30 \,N$ act at the ends $A$ and $B$ of a rod $1.5 \,m$ long. The resultant of the forces will act at the point ........
Medium
View Solution$A$ ladder rests against a frictionless vertical wall,with its upper end $6 \, m$ above the ground and the lower end $4 \, m$ away from the wall. The weight of the ladder is $500 \, N$ and its center of gravity ($C$.$G$.) is at $1/3$ of its length from the lower end. The reaction force from the wall will be (in Newton):
Medium
View Solution$A$ box of mass $m$ is in equilibrium under the application of three forces as shown below. If the magnitude of $F_1$ is $10 \ N$, what is the magnitude of $F_3$ (in $N$)?
When an object is in equilibrium state,then
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo