A block is lying at rest inside a bus. What i | vedclass

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(D) When the bus accelerates forward with acceleration $a$,a pseudo force $F_p = ma$ acts on the block in the backward direction relative to the bus.F

Vedclass · Accepted Answer

$2 \ m/s^2$

Vedclass · Answer

(D) When the bus accelerates forward with acceleration $a$,a pseudo force $F_p = ma$ acts on the block in the backward direction relative to the bus.For the block to remain stationary relative to the bus,the static friction force $f_s$ must balance this pseudo force.The maximum static friction force is given by $f_{s,max} = \mu N = \mu mg$.For the block to remain stationary,the pseudo force must be less than or equal to the maximum static friction force:$ma \leq \mu mg$$a \leq \mu g$Substituting the given values:$a \leq 0.2 	imes 10 \ m/s^2$$a \leq 2 \ m/s^2$Therefore,the maximum acceleration of the bus such that the block remains stationary is $2 \ m/s^2$.

$A$ block is lying at rest inside a bus. What is the maximum acceleration of the bus such that the block remains stationary? (The static friction coefficient $\mu = 0.2$,acceleration due to gravity $g = 10 \ m/s^2$)

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