A body of mass 5 kg starts from the origin w | vedclass

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(C) Given: Mass $m = 5 \ kg$,initial velocity $u = 30 \hat{i} + 40 \hat{j} \ ms^{-1}$,and force $F = -(\hat{i} + 5 \hat{j}) \ N$.We focus on the $y$-c

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$40$

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(C) Given: Mass $m = 5 \ kg$,initial velocity $u = 30 \hat{i} + 40 \hat{j} \ ms^{-1}$,and force $F = -(\hat{i} + 5 \hat{j}) \ N$.We focus on the $y$-component of motion.Initial $y$-velocity $u_y = 40 \ ms^{-1}$ and $y$-component of force $F_y = -5 \ N$.Using Newton's second law,the acceleration along the $y$-axis is $a_y = \frac{F_y}{m} = \frac{-5 \ N}{5 \ kg} = -1 \ ms^{-2}$.We want to find the time $t$ when the final $y$-velocity $v_y = 0$.Using the first equation of motion $v_y = u_y + a_y t$:$0 = 40 + (-1)t$$t = 40 \ s$.

$A$ body of mass $5 \ kg$ starts from the origin with an initial velocity $u = 30 \hat{i} + 40 \hat{j} \ ms^{-1}$. When a constant force $F = -(\hat{i} + 5 \hat{j}) \ N$ acts on the body,the time in which the $y$-component of the velocity becomes zero is (in $s$)

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