$A$ bar magnet of length $10 \text{ cm}$ and having the pole strength equal to $10^{-3} \text{ A-m}$ is kept in a magnetic field having magnetic induction $B$ equal to $4 \pi \times 10^{-3} \text{ T}$. It makes an angle of $30^{\circ}$ with the direction of magnetic induction. The value of the torque acting on the magnet is

• A
  $2 \pi \times 10^{-7} \text{ Nm}$
• B
  $2 \pi \times 10^{-5} \text{ Nm}$
• C
  $0.5 \text{ Nm}$
• D
  $0.5 \times 10^2 \text{ Nm}$