A weightless bag is filled with 5 ,kg of wate | vedclass

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(D) The apparent weight of an object submerged in a fluid is given by the formula: $W_{app} = W_{actual} - F_B$, where $W_{actual}$ is the actual weig

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(D) The apparent weight of an object submerged in a fluid is given by the formula: $W_{app} = W_{actual} - F_B$, where $W_{actual}$ is the actual weight and $F_B$ is the buoyant force.For an object of volume $V$ and density $\rho_{obj}$ submerged in a fluid of density $\rho_{fluid}$, the buoyant force is $F_B = V \rho_{fluid} g$.The actual weight of the bag is $W_{actual} = m g = V \rho_{obj} g$.Since the bag is filled with water, the density of the object (water) is equal to the density of the surrounding fluid (water), i.e., $\rho_{obj} = \rho_{fluid}$.Therefore, $W_{app} = V \rho_{obj} g - V \rho_{fluid} g = 0$.Thus, the reading of the spring balance is $0 \,kg$.

$A$ weightless bag is filled with $5 \,kg$ of water and is weighed in water using a spring balance. The reading of the spring balance is (in $\,kg$)

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