$A 3 \ m$ long steel wire is stretched to increase its length by $0.3 \ cm$. Poisson's ratio for steel is $0.26$. The lateral strain produced in the wire is

Liquids have no Poisson's ratio,because

There is no change in the volume of a wire due to a change in its length on stretching. The Poisson's ratio of the material of the wire is:

The relation between Young's modulus $(Y)$,modulus of rigidity $(\eta)$,and bulk modulus $(K)$ for an elastic material is:

$A$ wire of length $L$ and radius $r$ is loaded with a weight $Mg$. If $Y$ and $\sigma$ denote the Young's modulus and Poisson's ratio of the material of the wire respectively,then the decrease in the radius of the wire $(\Delta r)$ is given by:

$A$ material has a Poisson's ratio $0.5$. If a uniform rod of this material suffers a longitudinal strain of $2 \times 10^{-3}$,then the percentage change in its volume is