$A$ material has Poisson's ratio $0.50$. If a uniform rod made of this material suffers a longitudinal strain of $2 \times 10^{-3}$,then the percentage change in volume is

$A$ cylindrical wire of radius $1\, mm$,length $1\, m$,Young's modulus $Y = 2 \times 10^{11}\, N/m^2$,and Poisson's ratio $\mu = \pi / 10$ is stretched by a force of $100\, N$. What will be its new radius (in $, mm$)?

For silver,Young's modulus is $7.25 \times 10^{10} \ N/m^2$ and Bulk modulus is $11 \times 10^{10} \ N/m^2$. Its Poisson's ratio will be

For a homogeneous isotropic material, which one of the following cannot be the value of Poisson’s ratio?

$A$ wire of length $L$ and radius $r$ is loaded with a weight $Mg$. If $Y$ and $\sigma$ denote the Young's modulus and Poisson's ratio of the material of the wire respectively,then the decrease in the radius of the wire $(\Delta r)$ is given by:

The increase in length on stretching a wire is $0.05\%$. If its Poisson's ratio is $0.4$,then its diameter