A simple pendulum,suspended from the ceiling | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The time period of a simple pendulum is given by $T = 2 \pi \sqrt{\frac{l}{g_{eff}}}$.When the lift is at rest,the effective acceleration due to g

Vedclass · Accepted Answer

$\frac{T}{2}$

Vedclass · Answer

(D) The time period of a simple pendulum is given by $T = 2 \pi \sqrt{\frac{l}{g_{eff}}}$.When the lift is at rest,the effective acceleration due to gravity is $g_{eff} = g$.So,$T = 2 \pi \sqrt{\frac{l}{g}}$ ...$(i)$When the lift moves upwards with an acceleration $a = 3g$,the effective acceleration due to gravity becomes $g_{eff} = g + a = g + 3g = 4g$.The new time period $T^{\prime}$ is given by $T^{\prime} = 2 \pi \sqrt{\frac{l}{4g}}$.$T^{\prime} = \frac{1}{2} 	imes 2 \pi \sqrt{\frac{l}{g}}$.Substituting the value from Eq. $(i)$,we get $T^{\prime} = \frac{T}{2}$.

$A$ simple pendulum,suspended from the ceiling of a lift,has a period of oscillation $T$,when the lift is at rest. If the lift starts moving upwards with an acceleration $a = 3g$,then the new period will be

Similar Questions

State the laws of a simple pendulum.

If the length of a second's pendulum is decreased by $2\%$,how many seconds will it lose per day?

Can a simple pendulum clock be used in an artificial satellite? Why?

$A$ simple pendulum keeps correct time at $0^{\circ}C$. At $25^{\circ}C$,it loses $12.5 \, s$ in a day. What is the coefficient of linear expansion of the metal of the pendulum?

Two pendulums of length $121 \ cm$ and $100 \ cm$ start vibrating in phase. At some instant,the two are at their mean position in the same phase. The minimum number of vibrations of the shorter pendulum after which the two are again in phase at the mean position is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module