$XeF_2$ is hydrolyzed in the presence of a small amount of water. What are the gaseous products formed?
- A$Xe, O_2$
- B$F_2, O_2$
- C$Xe, O_3$
- D$O_2, F_2, Xe$
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Similar Questions
Select the incorrect statement.
Easy
View SolutionConsider the following transformations:
$I. XeF_6 + NaF \to Na^+[XeF_7]^-$
$II. 2PCl_{5(s)} \to [PCl_4]^+[PCl_6]^-$
$III. [Al(H_2O)_6]^{3+} + H_2O \to [Al(H_2O)_5OH]^{2+} + H_3O^+$
Which of the above transformations are correct?
$I. XeF_6 + NaF \to Na^+[XeF_7]^-$
$II. 2PCl_{5(s)} \to [PCl_4]^+[PCl_6]^-$
$III. [Al(H_2O)_6]^{3+} + H_2O \to [Al(H_2O)_5OH]^{2+} + H_3O^+$
Which of the above transformations are correct?
State the uses of noble gases.
Difficult
View SolutionAssertion $(A)$: $Xe$ atoms in $XeF_2$ are $d^2 s p^3$ hybridised.
Reason $(R)$: $XeF_2$ molecule does not follow the octet rule.
Which of the following is correct?
Reason $(R)$: $XeF_2$ molecule does not follow the octet rule.
Which of the following is correct?
Which of the following does not exist?
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