Class 11MathematicsPermutation and CombinationDefinition of permutation, Number of permutations with or without repetition, Conditional permutations
Difficult$10$ men and $6$ women are to be seated in a row so that no two women sit together. The number of ways they can be seated is:
- A$11! 10!$
- B$\frac{11!}{6! 5!}$
- C$\frac{10! 9!}{5!}$
- D$\frac{11! 10!}{5!}$
Explore More
Similar Questions
How many numbers can be formed using the digits $3, 4, 5, 6, 7, 8$ that lie between $3000$ and $4000$ and are divisible by $5$,given that repetition of digits is not allowed?
Medium
View SolutionIn how many ways can $6$ people be arranged in a row such that $A, B, C,$ and $D$ always appear in the order $ABCD$ (not necessarily together)?
Difficult
View SolutionAll the letters of the word $MOTHER$ are arranged in all possible ways and the resulting words (may or may not have meaning) are arranged as in the dictionary. The number of words that appear after the word $MOTHER$ is
In how many ways can $6$ examination papers be arranged so that the best and the worst papers are never together?
Difficult
View SolutionThe number of natural numbers less than $1000$,in which no two digits are repeated,is:
DifficultTS EAMCET 2006
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo