sin left(frac{5 pi}{3}right) + sec left(frac{ | vedclass

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Question

(A) We have $\sin \left(\frac{5 \pi}{3}\right) + \sec \left(\frac{13 \pi}{3}\right)$.First,simplify $\sin \left(\frac{5 \pi}{3}\right) = \sin \left(2

Vedclass · Accepted Answer

$2 - \frac{\sqrt{3}}{2}$

Vedclass · Answer

(A) We have $\sin \left(\frac{5 \pi}{3}\right) + \sec \left(\frac{13 \pi}{3}\right)$.First,simplify $\sin \left(\frac{5 \pi}{3}\right) = \sin \left(2 \pi - \frac{\pi}{3}\right) = -\sin \left(\frac{\pi}{3}\right) = -\frac{\sqrt{3}}{2}$.Next,simplify $\sec \left(\frac{13 \pi}{3}\right) = \sec \left(4 \pi + \frac{\pi}{3}\right) = \sec \left(\frac{\pi}{3}\right) = 2$.Adding these values,we get $-\frac{\sqrt{3}}{2} + 2 = 2 - \frac{\sqrt{3}}{2}$.Thus,the correct option is $A$.

$\sin \left(\frac{5 \pi}{3}\right) + \sec \left(\frac{13 \pi}{3}\right) = $

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