A square is formed by the lines x=0, y=0, x=1 | vedclass

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(C) The vertices of the square are $O(0,0), A(1,0), B(1,1),$ and $C(0,1)$.The diagonals are the line segments connecting opposite vertices,which are $

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$y=x, x+y=1$

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(C) The vertices of the square are $O(0,0), A(1,0), B(1,1),$ and $C(0,1)$.The diagonals are the line segments connecting opposite vertices,which are $OB$ and $AC$.$1$. Equation of diagonal $OB$ passing through $(0,0)$ and $(1,1)$:The slope $m = \frac{1-0}{1-0} = 1$.Using the point-slope form $y - y_1 = m(x - x_1)$:$y - 0 = 1(x - 0) \Rightarrow y = x$.$2$. Equation of diagonal $AC$ passing through $(1,0)$ and $(0,1)$:The slope $m = \frac{1-0}{0-1} = -1$.Using the point-slope form $y - 0 = -1(x - 1)$:$y = -x + 1 \Rightarrow x + y = 1$.Thus,the equations of the diagonals are $y = x$ and $x + y = 1$.

$A$ square is formed by the lines $x=0, y=0, x=1, y=1$. Then,the equations of its diagonals will be

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