$A$ prism $(\mu=1.5)$ has a refracting angle of $30^{\circ}$. The deviation of a monochromatic ray incident normally on one of its surfaces will be (given,$\sin 48^{\circ} 36^{\prime}=0.75$):

$A$ triangular prism of glass is shown in the figure. $A$ ray incident normally to one face is totally reflected,if $\theta = 45^o$. The index of refraction of glass is

In the given figure,the face $AC$ of the equilateral prism is immersed in a liquid of refractive index $n$. For an incident angle of $60^{\circ}$ at the side $AC$,the refracted light beam just grazes along the face $AC$. The refractive index of the liquid is $n = \frac{\sqrt{x}}{4}$. The value of $x$ is (Given refractive index of glass $= 1.5$)

For the angle of minimum deviation of a prism to be equal to its refracting angle,the prism must be made of a material whose refractive index

$A$ ray of light is incident at an angle of incidence '$i$' on one surface of a thin prism of small angle '$A$'. The ray emerges normally from the opposite surface. If the refractive index of the material of the prism is '$\mu$',the angle of incidence '$i$' is nearly equal to

$A$ light ray is incident normally on one surface of an equilateral prism. The angle of deviation of the light ray is (refractive index of the material of the prism $=\sqrt{2}$) (in $^{\circ}$)