A ray of light passes through an equilateral | vedclass

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(D) For an equilateral prism,the angle of the prism $A = 60^{\circ}$.Given that the angle of incidence $i$ is equal to the angle of emergence $e$,and

Vedclass · Accepted Answer

$30$

Vedclass · Answer

(D) For an equilateral prism,the angle of the prism $A = 60^{\circ}$.Given that the angle of incidence $i$ is equal to the angle of emergence $e$,and both are equal to $3/4$ of the angle of the prism:$i = e = \frac{3}{4} 	imes A = \frac{3}{4} 	imes 60^{\circ} = 45^{\circ}$.The relationship between the angle of incidence,angle of emergence,angle of the prism,and the angle of deviation $\delta$ is given by:$i + e = A + \delta$Substituting the known values into the equation:$45^{\circ} + 45^{\circ} = 60^{\circ} + \delta$$90^{\circ} = 60^{\circ} + \delta$$\delta = 90^{\circ} - 60^{\circ} = 30^{\circ}$.Thus,the angle of deviation is $30^{\circ}$.

$A$ ray of light passes through an equilateral prism such that the angle of incidence is equal to the angle of emergence and each one is equal to $3/4$th the angle of the prism. The angle of deviation is (in $^{\circ}$)

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