$2 Cu_2O_{(s)} + Cu_2S_{(s)} \longrightarrow 6 Cu_{(s)} + SO_{2(g)}$
In the above reaction,the oxidant and reductant respectively are:

  • A
    $Cu(I)$ of $Cu_2O$ and sulphide of $Cu_2S$
  • B
    sulphide of $Cu_2S$ and $Cu(I)$ of $Cu_2O$
  • C
    $Cu(I)$ of $Cu_2O$ and $Cu_2S$,and sulphide of $Cu_2S$
  • D
    $Cu(I)$ of $Cu_2S$ and $Cu(I)$ of $Cu_2O$

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