A crystal of intrinsic silicon at room temper | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given:Intrinsic carrier concentration,$n_i = 1.6 	imes 10^{16} / m^3$Donor concentration,$n_e \approx N_D = 4.8 	imes 10^{20} / m^3$According to

Vedclass · Accepted Answer

$5.3 	imes 10^{11} / m^3$

Vedclass · Answer

(D) Given:Intrinsic carrier concentration,$n_i = 1.6 	imes 10^{16} / m^3$Donor concentration,$n_e \approx N_D = 4.8 	imes 10^{20} / m^3$According to the law of mass action for semiconductors,the product of electron and hole concentrations is equal to the square of the intrinsic carrier concentration:$n_e 	imes n_h = n_i^2$Substituting the given values:$4.8 	imes 10^{20} 	imes n_h = (1.6 	imes 10^{16})^2$$4.8 	imes 10^{20} 	imes n_h = 2.56 	imes 10^{32}$$n_h = \frac{2.56 	imes 10^{32}}{4.8 	imes 10^{20}}$$n_h = 0.533 	imes 10^{12} / m^3 = 5.33 	imes 10^{11} / m^3$Thus,the concentration of holes is approximately $5.3 	imes 10^{11} / m^3$.

$A$ crystal of intrinsic silicon at room temperature has a carrier concentration of $1.6 \times 10^{16} / m^3$. If the donor concentration level is $4.8 \times 10^{20} / m^3$,then the concentration of holes in the semiconductor is

Similar Questions

If $I_n = \int_0^{\pi / 4} \tan^n x \, dx$, then $I_2+I_4, I_3+I_5, I_4+I_6, \ldots$ are in

What is the function of nitrifying bacteria?

$A$ class has $15$ boys and $5$ girls. Suppose $3$ students are selected at random from the class. The probability that there are $2$ boys and $1$ girl is

The line passing through $\left(-1, \frac{\pi}{2}\right)$ and perpendicular to $\sqrt{3} \sin \theta + 2 \cos \theta = \frac{4}{r}$ is :

$\frac{d}{d x} \sin ^{-1}\left(3 x-4 x^3\right)$ is equal to

Vedclass Test Series

Exam Paper Generator

Online Exam Module