$A$ family consists of $8$ persons. If $4$ persons are chosen at random and they are found to be $2$ men and $2$ women,then the probability that there are equal number of men and women in that family is

  • A
    $\frac{1}{5}$
  • B
    $\frac{3}{7}$
  • C
    $\frac{2}{5}$
  • D
    $\frac{2}{7}$

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