$7$ coins are tossed simultaneously and the number of heads turned up is denoted by the random variable $X$. If $\mu$ is the mean and $\sigma^2$ is the variance of $X$,then $\frac{\mu \sigma^2}{P(X=3)}=$

  • A
    $\frac{56}{5}$
  • B
    $\frac{84}{5}$
  • C
    $\frac{112}{5}$
  • D
    $\frac{224}{5}$

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