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(C) In an $hcp$ lattice,the number of atoms of $O$ is $N = 6$.Number of octahedral voids $= N = 6$.Number of tetrahedral voids $= 2N = 12$.Atoms of $A

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$ABO_2$

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(C) In an $hcp$ lattice,the number of atoms of $O$ is $N = 6$.Number of octahedral voids $= N = 6$.Number of tetrahedral voids $= 2N = 12$.Atoms of $A$ occupy $25\%$ of tetrahedral voids: $A = 0.25 	imes 12 = 3$.Atoms of $B$ occupy $50\%$ of octahedral voids: $B = 0.50 	imes 6 = 3$.Atoms of $O$ in $hcp$ lattice $= 6$.The ratio of atoms $A:B:O$ is $3:3:6$,which simplifies to $1:1:2$.Therefore,the molecular formula is $ABO_2$.

$A$ solid compound is formed by atoms of $A$ (cations),$B$ (cations),and $O$ (anions). Atoms of $O$ form an $hcp$ lattice. Atoms of $A$ occupy $25\%$ of the tetrahedral voids,and atoms of $B$ occupy $50\%$ of the octahedral voids. What is the molecular formula of the solid?

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