$A$ cubic lattice has atoms of $A$ at the body centre,atoms of $B$ at the corners of the cube and atoms $C$ at all the face centres. What is its formula?

$A$ cubic structure is formed where atoms of element $X$ are occupied at the corners of the cube and also at the face centers. Atoms of element $Y$ are present at the body center and at the edge centers. If all the atoms are removed along a plane passing through the middle of the cube (bisecting the four edges), the formula will become

In a compound,$W$ atoms are at the corners of the unit cell,$O$ atoms are at the edges of the unit cell,and $Na$ atoms are at the body center. The molecular formula of the compound is:

In calcium fluoride,having the fluorite structure,the coordination numbers for calcium ion $(Ca^{2+})$ and fluoride ion $(F^{-})$ are

$A$ solid $AB$ has a $ZnS$ type structure. If the radius of the $B^-$ ion is $100 \, pm$, what is the minimum radius of the $A^+$ cation in $pm$?

What is the coordination number of a cation in an ionic compound if the type of hole occupied by the cation is cubic?