$A$ metal $(X)$ of atomic weight $M \ g \ mol^{-1}$ crystallizes in a $bcc$ lattice. Its density is $d \ g \ cm^{-3}$. What is the equation for the unit cell edge length $(a)$? ($N=$ Avogadro number)
- A$a = \left( \frac{2M}{Nd} \right)^{\frac{1}{3}}$
- B$a = \left( \frac{2M}{Nd} \right)^{\frac{1}{2}}$
- C$a = \left( \frac{4M}{Nd} \right)^{\frac{1}{3}}$
- D$a = \left( \frac{M}{Nd} \right)^{\frac{1}{3}}$
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View SolutionCalculate the density of a metal having a molar mass of $210 \ g \ mol^{-1}$ that forms a simple cubic unit cell. $(a^3 \cdot N_{A} = 21.5 \ cm^3 \ mol^{-1})$ (in $g \ cm^{-3}$)
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