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(A) Two solutions having the same osmotic pressure at a given temperature are called isotonic solutions.For isotonic solutions,the molar concentration

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$2$

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(A) Two solutions having the same osmotic pressure at a given temperature are called isotonic solutions.For isotonic solutions,the molar concentrations are equal: $C_{	ext{urea}} = C_{	ext{solute}}$.$x \% (w/v)$ solution of urea means $x \ g$ of urea in $100 \ mL$ of solution. The molar mass of urea $(NH_2CONH_2)$ is $60 \ g \ mol^{-1}$.$C_{	ext{urea}} = \frac{x \ g}{60 \ g \ mol^{-1}} 	imes \frac{1000 \ mL}{100 \ mL} 	imes \frac{1}{1 \ L} = \frac{x}{6} \ M$.$4 \% (w/v)$ solution of non-volatile solute means $4 \ g$ of solute in $100 \ mL$ of solution. The molar mass of the solute is $120 \ g \ mol^{-1}$.$C_{	ext{solute}} = \frac{4 \ g}{120 \ g \ mol^{-1}} 	imes \frac{1000 \ mL}{100 \ mL} 	imes \frac{1}{1 \ L} = \frac{4}{12} \ M = \frac{1}{3} \ M$.Equating the concentrations: $\frac{x}{6} = \frac{1}{3}$.Solving for $x$: $x = \frac{6}{3} = 2$.

$x \% (w/v)$ solution of urea is isotonic with $4 \% (w/v)$ solution of a non-volatile solute of molar mass $120 \ g \ mol^{-1}$. The value of $x$ is

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