A cyclist comes to a skidding stop in 10 ,m. | vedclass

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(B) The displacement of the cyclist until coming to a stop is $s = 10 \,m$.The force exerted by the road on the cycle is $F = 200 \,N$.Since the force

Vedclass · Accepted Answer

$-2000 \,J$

Vedclass · Answer

(B) The displacement of the cyclist until coming to a stop is $s = 10 \,m$.The force exerted by the road on the cycle is $F = 200 \,N$.Since the force acts in the direction directly opposite to the motion (displacement),the angle between the force vector and the displacement vector is $	heta = 180^{\circ}$.The work done $W$ by a constant force is given by the formula $W = F s \cos 	heta$.Substituting the given values: $W = 200 \,N 	imes 10 \,m 	imes \cos 180^{\circ}$.Since $\cos 180^{\circ} = -1$,we get $W = 200 	imes 10 	imes (-1) = -2000 \,J$.Therefore,the work done by the road on the cycle is $-2000 \,J$.

$A$ cyclist comes to a skidding stop in $10 \,m$. During this process,the force on the cycle due to the road is $200 \,N$ and is directly opposite to the motion. How much work does the road do on the cycle?

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