$A$ primary alcohol was reacted with pyridinium chlorochromate $(PCC)$,which resulted in a product $P$. The product $P$ on treatment with ammoniacal silver nitrate solution produces:

In the following reaction:
$\text{Aldehyde} + \text{Alcohol} \xrightarrow{HCl} \text{Acetal}$
$HCHO \qquad ^tBuOH$
$CH_3CHO \qquad MeOH$
The best combination for the formation of acetal is:

The reaction sequence is as follows:
Benzene + $CH_3Cl$ $\xrightarrow{Anhy. AlCl_3} A$ $\xrightarrow[(2) H_3O^+, \Delta]{(1) CrO_3 / (CH_3CO)_2O, 273-283K} B$
The incorrect statement about '$B$' is:

An aldehyde or ketone containing at least one $\alpha-H$ atom reacts with dilute $NaOH$ to form a $\beta-$hydroxy aldehyde or $\beta-$hydroxy ketone. This reaction is known as $—$

In the reaction,$C_6H_5COCH_3 \xrightarrow[Zn-Hg / \text{conc. } HCl]{[H]} X$,$X$ is

$A$ compound of molecular formula $C_8H_8O_2$ reacts with acetophenone to form a single cross-aldol product in the presence of base. The same compound on reaction with conc. $NaOH$ forms benzyl alcohol as one of the products. The structure of the compound is