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(B) The power produced by the generator is $P = V 	imes I = 4000 \, V 	imes 100 \, A = 4 	imes 10^5 \, W$.Since the transformer is ideal, the power

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$0.05$

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(B) The power produced by the generator is $P = V 	imes I = 4000 \, V 	imes 100 \, A = 4 	imes 10^5 \, W$.Since the transformer is ideal, the power remains constant. The current in the transmission line $(I')$ is given by $P = V' 	imes I'$, where $V' = 2 	imes 10^5 \, V$.$I' = P / V' = (4 	imes 10^5 \, W) / (2 	imes 10^5 \, V) = 2 \, A$.The power loss in the transmission line is $P_{loss} = (I')^2 	imes R = (2 \, A)^2 	imes 50 \, \Omega = 4 	imes 50 = 200 \, W$.The percentage of power loss is $(P_{loss} / P) 	imes 100 = (200 / 4 	imes 10^5) 	imes 100 = (2 	imes 10^2 / 4 	imes 10^5) 	imes 10^2 = 0.5 	imes 10^{-1} 	imes 10^2 = 0.05 \%$.

$A$ generator produces a current of $100 \, A$ at $4000 \, V$. The voltage is stepped up to $2 \times 10^5 \, V$ by a transformer before being sent on a high voltage transmission line of resistance $50 \, \Omega$. The percentage of power loss in the transmission line is (in $\%$)

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