A molecule (X) has (i) four sigma bonds forme | vedclass

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(D) In ethene $(C_2H_4)$,each carbon atom is $sp^2$ hybridized.Each carbon atom forms two $\sigma$ bonds with hydrogen atoms by the overlap of $sp^2$

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$C_2H_4$

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(D) In ethene $(C_2H_4)$,each carbon atom is $sp^2$ hybridized.Each carbon atom forms two $\sigma$ bonds with hydrogen atoms by the overlap of $sp^2$ and $s$ orbitals. Since there are two carbon atoms,there are $2 	imes 2 = 4$ such $\sigma$ bonds.The two carbon atoms are bonded to each other by a $\sigma$ bond formed by the overlap of $sp^2$ and $sp^2$ orbitals.Additionally,the unhybridized $p_z$ orbitals of the two carbon atoms overlap laterally to form one $\pi$ bond.Thus,the molecule $(X)$ is $C_2H_4$.

$A$ molecule $(X)$ has $(i)$ four sigma bonds formed by the overlap of $sp^2$ and $s$ orbitals,(ii) one sigma bond formed by $sp^2$ and $sp^2$ orbitals,and (iii) one $\pi$ bond formed by $p_z$ and $p_z$ orbitals. Which of the following is $X$?

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