A circular coil of area 3 times 10^{-2} , m^2 | vedclass

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Question

(A) Given: Area $A = 3 	imes 10^{-2} \, m^2$, Number of turns $N = 900$, Resistance $R = 1.8 \, \Omega$, Magnetic field $B = 3.5 	imes 10^{-5} \, T$

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$2.1$

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(A) Given: Area $A = 3 	imes 10^{-2} \, m^2$, Number of turns $N = 900$, Resistance $R = 1.8 \, \Omega$, Magnetic field $B = 3.5 	imes 10^{-5} \, T$, Time $t = 0.5 \, s$.Initial magnetic flux $\phi_i = N B A \cos(0^{\circ}) = N B A$.Final magnetic flux $\phi_f = N B A \cos(180^{\circ}) = -N B A$.Change in flux $\Delta \phi = \phi_f - \phi_i = -2 N B A$.Induced $EMF$ $\varepsilon = -\frac{\Delta \phi}{\Delta t} = \frac{2 N B A}{t}$.Induced current $I = \frac{\varepsilon}{R} = \frac{2 N B A}{R t}$.Substituting the values: $I = \frac{2 	imes 900 	imes 3.5 	imes 10^{-5} 	imes 3 	imes 10^{-2}}{1.8 	imes 0.5}$.$I = \frac{1800 	imes 10.5 	imes 10^{-7}}{0.9} = 2000 	imes 10.5 	imes 10^{-7} = 21000 	imes 10^{-7} = 2.1 	imes 10^{-3} \, A = 2.1 \, mA$.

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