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(C) According to Faraday's Law of Electromagnetic Induction,the induced electromotive force $(EMF)$ in a coil is given by the rate of change of magnet

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$\frac{\pi}{10} \ V$

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(C) According to Faraday's Law of Electromagnetic Induction,the induced electromotive force $(EMF)$ in a coil is given by the rate of change of magnetic flux linkage.$|\varepsilon| = N \left| \frac{d\phi}{dt} ight| = N A \left| \frac{dB}{dt} ight|$Given:Number of turns $N = 100$Radius $r = 10 \ cm = 0.1 \ m$Area $A = \pi r^2 = \pi 	imes (0.1)^2 = 0.01 \pi \ m^2$Rate of change of magnetic field $\frac{dB}{dt} = 0.1 \ T \ s^{-1}$Substituting the values:$|\varepsilon| = 100 	imes (0.01 \pi) 	imes 0.1$$|\varepsilon| = 1 	imes 0.1 \pi = 0.1 \pi \ V = \frac{\pi}{10} \ V$

$A$ flat circular coil has $100$ turns of wire of radius $10 \ cm$. $A$ uniform magnetic field exists in a direction perpendicular to the plane of the coil and it grows at a rate of $0.1 \ T \ s^{-1}$. The induced emf in the coil is:

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